| MATH500 IDX=16 | Okay, so I have this math problem here: Compute 1−2+3−4+5−⋯+99−100 . Hmm, let me try to figure this out step by step. First, I notice that the series alternates between adding and subtracting consecutive numbers. It starts with 1, then subtracts 2, adds 3, subtracts 4, and so on, all the way up to subtracting 100. So, the pattern is +1,−2,+3,−4,…,+99,−100 . I wonder if there’s a way to group these terms to make it easier to compute. Maybe if I pair them up? Let me try that. If I group the first two terms: 1−2 , that equals −1 . Then the next two terms: 3−4 , which is also −1 . Hmm, interesting. Let me check the next pair: 5−6=−1 . It seems like every pair of consecutive numbers adds up to −1 . So, if each pair is −1 , how many such pairs are there in the series? Well, the series goes from 1 to 100, so that’s 100 terms in total. If I pair them two at a time, that would be 100/2=50 pairs. Therefore, if each pair is −1 , the total sum should be 50×(−1)=−50 . Wait, let me make sure I didn’t make a mistake here. So, starting from 1, subtracting 2, adding 3, subtracting 4, etc., up to 100. So, each pair is indeed two numbers, one positive and one negative, with the positive being odd and the negative being even. Let me write out the first few pairs to confirm:1 - 2 = -13 - 4 = -15 - 6 = -17 - 8 = -1…99 - 100 = -1. Yes, each pair is -1, and there are 50 such pairs because 100 divided by 2 is 50. So, 50 times -1 is -50. Is there another way to think about this? […] the final answer is: − 50 | To solve the problem 1−2+3−4+5−⋯+99−100 , we can break it down into manageable steps. 1. Understand the Pattern: The sequence alternates between positive and negative terms. Specifically, the terms are 1,−2,3,−4,5,−6,…,99,−100 . 2. Group the Terms: We can group the terms in pairs: (1−2),(3−4),(5−6),…,(99−100) . Each pair sums to −1 . 3. Count the Pairs: Since we are pairing every two terms, and there are 100 terms in total, there will be 100/2=50 pairs. 4. Sum the Pairs: Since each pair sums to −1 , the total sum will be 50×(−1)=−50 . Let’s implement this in Python to verify our reasoning.“‘python# Calculate the sum of the series 1 - 2 + 3 - 4 + 5 - … + 99 - 100 total_sum = 0# Iterate through the series for i in range(1, 101): if i % 2 == 0: # if i is even, subtract it total_sum -= i else: # if i is odd, add it total_sum += i print(total_sum)“““output-50“‘ The sum of the series 1−2+3−4+5−⋯+99−100 is −50 . |