stat.MLOct 9, 2026

Hitting-Time Bounds for Asynchronous Q-Learning

Authors: Yang Peng

Organizations: Yau Mathematical Sciences Center, Tsinghua University

Abstract

We study the last iterate of standard asynchronous Q-learning from a single trajectory of a finite Markov decision process. The trajectory follows a fixed behavior policy whose state--action chain is irreducible and may be periodic. For discount factor γγ, write H=(1−γ)−1H=(1-γ)^{-1}, and let μmin⁡μ_{\min} be the minimum stationary state--action probability and h⋆\mathfrak h_\star the largest expected hitting time of the reverse state--action chain. We prove that zero-initialized Q-learning with a constant step size achieves sup-norm error at most ε\varepsilon with high probability using O~(H4/(μmin⁡ε2)+h⋆)\widetilde{O}(H^4/(μ_{\min}\varepsilon^2)+\mathfrak h_\star) transitions, for 0<ε≤10<\varepsilon\le1. The statistical term retains the quartic effective-horizon dependence of standard Q-learning, while initialization cost is additive in h⋆\mathfrak h_\star. For aperiodic behavior chains, a comparison with mixing time yields a transient term O~(tmix/μmin⁡)\widetilde{O}(t_{\mathrm{mix}}/μ_{\min}). An empirical state--action count rule selects a constant step size for a subsequent training run and attains the same rate without prior knowledge of model parameters, target accuracy, or confidence level. The output is the last training iterate, with both stages included in the sample count. The proof uses two deterministic Bellman envelopes to separate statistical error from fixed-policy initialization error and adapts reverse-time hitting-cost compensation from TD learning to state--action propagation. An exploration lower bound holds for arbitrary predictable step sizes. Together with the existing statistical lower bound and its extension to pilot-selected constant steps, it yields matching mean-square rates up to logarithmic factors on the stated large-sample parameter classes.

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