hep-phSep 30, 2026

PINNing the pion: conformal deep learning for Fπ(s)F_π(s) and the (g−2)μ(g-2)_μ hadronic contribution

Authors: Mayank Goel, Subhadip Mitra, Monalisa Patra

Organizations: Center for Computational Natural Sciences and Bioinformatics, International Institute of Information Technology, Hyderabad 500 032, India

Abstract

Extracting the pion electromagnetic form factor Fπ(s)F_π(s) through phenomenological curve-fitting models introduces model dependence, unphysical artefacts, and kinematic inconsistencies. We introduce a Physics-Informed Neural Network (PINN) embedded in a conformal zz-plane that constructs Fπ(s)F_π(s) directly from first principles across spacelike and timelike domains: charge normalisation and Schwarz reflection are enforced by construction, while Cauchy-Riemann analyticity, dispersion relations, Watson's theorem, and perturbative QCD asymptotics enter through the loss functional. Thus, the fundamental S-matrix principles dictate the form factor's behaviour while data act as constraints. Mapping the cut complex plane onto the unit disk bounds the Hessian norm and prevents Neural Tangent Kernel spectral starvation, two known failure modes of deep-learning optimisation. Besides e+e−e^+e^- scattering data, we also incorporate ττ-decay data through a switch that isolates the pure isovector form factor natively, bypassing model-dependent isospin-breaking pre-corrections. The network organically yields an interior zero-free form factor, while the framework tests experimental tensions around the ρ(770)ρ(770) peak against analyticity and dispersion constraints. We obtain model-independent estimates of the pion charge radius, ⟨rπ2⟩=0.435±0.008stat±0.007cali\langle r_π^2 \rangle = 0.435 \pm 0.008_{\text{stat}} \pm 0.007_{\text{cali}} fm2^2, the second-sheet pole parameters, mρpole=761.72±1.04m_ρ^{\text{pole}} = 761.72\pm 1.04 MeV and Γρpole=135.99±1.20Γ_ρ^{\text{pole}} = 135.99 \pm 1.20 MeV, and the two-pion contribution to the muon anomalous magnetic moment, aμππ=(506.48±2.02stat±1.70cali)×10−10a_μ^{ππ} = (506.48 \pm 2.02_{\text{stat}} \pm 1.70_{\text{cali}}) \times 10^{-10}.

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